- What the iPad 3′s Retina display looks like under a microscope



DoDIIS

Please click on the following link to view the article.
http://www.ncsi.com/dodiis12/index.html


Evolution of Google.com

<br />Created by Online PhD



Some Awesomeness from the Folks at the W3C

Dynamic outlines: the 'outline' property

The 'outline-color' accepts all colors, as well as the keyword 'invert'

'Invert' is expected to perform a color inversion on the pixels on the screen. 

This is a common trick to ensure the focus border is visible, regardless of color background.

  1. Outlines do not take up space.
  2. Outlines may be non-rectangular.
Outlines have been around since CSS2.1, but hadn't heard about them.

Enjoy!


Play Star Wars Episode IV

Using a simple telnet address you Terminal will connect in and play Star Wars Episode IV in its ASCII glory:

telnet towel.blinkenlights.nl



jQuery

So I have heard so much about the time saving goodness of JavaScript frameworks that I decided to see about it myself. Wow. I've been wasting time and keystrokes.

It took me about ten seconds to permanently switch to jQuery.

Compare the difference between the following two JavaScript fragments:

Non jQuery: document.getElementById("iframe").src = url;

jQuery: $('#iframe').load(url);

See what I mean?!



Resetting Favicons on Apple Safari Web Browser

safari file menu
      Favicons not changing on Safari (after all your hard work)?
      Here is the solution (hidden in plain sight).
reset safari
Reset/Renew Safari favicons:
      After you click Reset, reload your page and be happy!


Lytro



Validate CSS3

Are you using CSS3 and wonder why the CSS even has the standard if they won't validate perfectly legal CSS3 code? All you have to do is hack the badge code.
Here is the code provided by W3C for CSS validation badge:

http://jigsaw.w3.org/css-validator/check/referer
Just add
?profile=css3
so that it looks like this:
http://jigsaw.w3.org/css-validator/check/referer?profile=css3


Pi in Hexidecimal?

Ya, there's (Python) code for that:

def pi():
N = 0
n, d = 0, 1
while True:
xn = (120*N**2 + 151*N + 47)
xd = (512*N**4) + 1024*N**3 +
712*N**2 + 194*N + 15)
n = ((16 * n * xd) + (xn * d)) % (d * xd)
d *= xd
yield 16 * n // d
N += 1